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thehidden
ok not sure how this riddle will work not on paper butt

There is a horse with a 15 foot rope tied to it. there is a large bail of hay 25 feet from the horse. how does it eat from the hay?
coesillian
QUOTE (thehidden @ Friday, November 24th, 2006, 3:02 PM) *
ok not sure how this riddle will work not on paper butt

There is a horse with a 15 foot rope tied to it. there is a large bail of hay 25 feet from the horse. how does it eat from the hay?


if a rope is tied to a horse but not fixed to anything else then the horse will just walk over there.
thehidden
QUOTE (coesillian @ Friday, November 24th, 2006, 12:05 PM) *
if a rope is tied to a horse but not fixed to anything else then the horse will just walk over there.



good man! lots of people generally over look the not being tied up, just assume he was
DrawingDeadInDM
QUOTE (coesillian @ Friday, November 24th, 2006, 11:58 AM) *
Ok actuary I gotta try harder...

A detective shows up at a crime scene where a person is found dead, hanging from the celling with a rope around their neck and a pool of water on the floor beath the deceased. the person was to short to jump and grab the rope and hoist themselves up. There is no chair, no ladder, no furniture near where the body is hanging. What seems like a homicide is actually declared a suicide by the detective, why?


He was standing on a block of ice, the ice melted, night night.
Jerry
Hay <---10feet----->X<---------15feet----------> Horse

<--------------------25feet-------------------->
DrawingDeadInDM
QUOTE (Jerry @ Friday, November 24th, 2006, 12:26 PM) *
He stood on a block of ice and waited until it melted?


14 minutes too late, old man.
coesillian
when does 11 + 2 = 1?
augmented
QUOTE (coesillian @ Friday, November 24th, 2006, 12:41 PM) *
when does 11 + 2 = 1?


clocks?

11:00 + 2 hours = 1:00

here's a similar one:

move one digit in the following equation to make it true.

101 - 102 = 1
gkunit20
QUOTE (DrawingDeadInDM @ Friday, November 24th, 2006, 1:41 PM) *
"As I was going to St. Ives, I met a man with seven wives..the seven wives had seven cats, the seven cats had seven kittens, how many were going to St. Ives?" --Jeremy Irons



1 person.
LongLiveYorke
Here's a good one:



You have two ropes. You know for a fact that it takes both of them exactly an hour to burn. However, you don't know what the ropes are made of. They don't burn at a constant speed, the burning could speed up at one place, slow down at another, we don't know. Both of the ropes could also be totally different from one another. All we know for a fact is that, in the end, whether they burn quickly in one place and slower in another, and whether or not they burn differently from one another, it takes them exactly one hour to burn completely.

Our task is to measure 45 minutes using these two ropes. We have to be 100% sure that we've measured 45 minutes, so taking averages or guessing doesn't work.

How do we do it?
thehidden
QUOTE (augmented @ Friday, November 24th, 2006, 1:00 PM) *
clocks?

11:00 + 2 hours = 1:00

here's a similar one:

move one digit in the following equation to make it true.

101 - 102 = 1



101-102=x
coesillian
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 4:27 PM) *
Here's a good one:
You have two ropes. You know for a fact that it takes both of them exactly an hour to burn. However, you don't know what the ropes are made of. They don't burn at a constant speed, the burning could speed up at one place, slow down at another, we don't know. Both of the ropes could also be totally different from one another. All we know for a fact is that, in the end, whether they burn quickly in one place and slower in another, and whether or not they burn differently from one another, it takes them exactly one hour to burn completely.

Our task is to measure 45 minutes using these two ropes. We have to be 100% sure that we've measured 45 minutes, so taking averages or guessing doesn't work.

How do we do it?


are the lengths of the ropes equal?
LongLiveYorke
QUOTE (coesillian @ Friday, November 24th, 2006, 4:38 PM) *
are the lengths of the ropes equal?



Hmm. The answer to this will be considered a hint:

It doesn't matter. We'll simply say, "no" to add to the generality of the riddle. They could be equal, or they could not be. Either way, the answer is the same.
AcesUp46
An Arab sheikh tells his two sons to race their camels to a distant city to see who will inherit his fortune. The one whose camel is slower will win.

The brothers, after wandering aimlessly for days, ask a wise man for advise. After hearing the advice they jump on the camels and race as fast as they can to the city. What does the wise man say?
qyayqi
QUOTE (Actuary @ Thursday, November 23rd, 2006, 10:06 PM) *
mines weak, but:

3 men go to hotel
Pay $10 each for room
Later manager realizes he's over charged the men $1 each.
He gives the bell hop a $5 bill and says: "Make change, and give each man back $1. You can keep the other $2 for your troubles"

bellhop pays each man back $1.

So, each man paid $9 for his room, and the bellhop kept $2.
That's $9 * 3 + $2 = $29

What happened to the other dollar?


the manager screwed the bellhop out of a dollar. or kept a $1 tip for himself, i guess. if he wanted to give the full tip to the bellhop he would have given him $6, the (3 x $1) + (30-27=3) = 6.

i'll keep reading and see if the answer was already posted.
coesillian
ummmm. open discussion is needed here I think.

45*2 is 1.5h, so if we knew when a rope was half done burning we could know when we reached 1.5 hours. But then we could know when a rope is 3/4 done burning also so this doesn't hold.. We can probably get some information from burning one of the ropes to completion first. Then we know 1h.

I got nothing
AcesUp46
QUOTE (coesillian @ Friday, November 24th, 2006, 1:51 PM) *
ummmm. open discussion is needed here I think.

45*2 is 1.5h, so if we knew when a rope was half done burning we could know when we reached 1.5 hours. But then we could know when a rope is 3/4 done burning also so this doesn't hold.. We can probably get some information from burning one of the ropes to completion first. Then we know 1h.

I got nothing


Burn rope 1 at both ends while at the same time burn rope 2 at one end. Once rope 1 is burnt, that's 30mins. That means that rope 2 (burning at 1 end has 30 mins left). Now immediately burn other end of rope 2. So instead of taking 30mins to burn through, it will burn in 15 mins.

Thus 45 mins.
gkunit20
QUOTE (AcesUp46 @ Friday, November 24th, 2006, 3:49 PM) *
An Arab sheikh tells his two sons to race their camels to a distant city to see who will inherit his fortune. The one whose camel is slower will win.

The brothers, after wandering aimlessly for days, ask a wise man for advise. After hearing the advice they jump on the camels and race as fast as they can to the city. What does the wise man say?


Switch Camels.
coesillian
QUOTE (AcesUp46 @ Friday, November 24th, 2006, 4:53 PM) *
Burn rope 1 at both ends while at the same time burn rope 2 at one end. Once rope 1 is burnt, that's 30mins. That means that rope 2 (burning at 1 end has 30 mins left). Now immediately burn other end of rope 2. So instead of taking 30mins to burn through, it will burn in 15 mins.

Thus 45 mins.


icon_clap.gif icon_clap.gif icon_clap.gif
LongLiveYorke
QUOTE (AcesUp46 @ Friday, November 24th, 2006, 4:53 PM) *
Burn rope 1 at both ends while at the same time burn rope 2 at one end. Once rope 1 is burnt, that's 30mins. That means that rope 2 (burning at 1 end has 30 mins left). Now immediately burn other end of rope 2. So instead of taking 30mins to burn through, it will burn in 15 mins.

Thus 45 mins.



YOU ARE CORRECT, SIR. See, by answering this correctly, you can now get any job you want at Microsoft, any consulting firm, and you an ace your LSAT's (really, all those things are basically riddles like this).

Okay, super hard one here:

(I'm not sure I fully understand the answer, but I'm coming to grips with it)



We are a king holding a party. At this party, we have 1,000 glasses of wine. However, an assassin trying to kill us or ruin our party has put poison in one glass of wine. The poison will leave whoever drinks it very sick, which is bad. The poison takes a day to go into effect, so we won't know the results of drinking it right away. As the king, we have many people who are willing to taste the wine for poison.

Our task is to figure out the least amount of people we would need to taste the wine and figure out exactly which glass of wine has the poison in it. We can assume that the tasters are allowed to drink from as many glasses as we choose. Assume that the glasses are large enough so arbitrarily many tasters can drink from any given glass.

Remember, the task isn't to minimize the amount of tasters who get sick (if it were we would hire 1,000 and have them each taste 1). Rather, it is to minimize the number of tasters we hire.

Hint: It is not necessary to come up with the exact strategy for tasting the glasses. I am only looking for the number of people we would need to figure out which glass the poison is in.
AcesUp46
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 2:10 PM) *
YOU ARE CORRECT, SIR. See, by answering this correctly, you can now get any job you want at Microsoft, any consulting firm, and you an ace your LSAT's (really, all those things are basically riddles like this).

Okay, super hard one here:

(I'm not sure I fully understand the answer, but I'm coming to grips with it)
We are a king holding a party. At this party, we have 1,000 glasses of wine. However, an assassin trying to kill us or ruin our party has put poison in one glass of wine. The poison will leave whoever drinks it very sick, which is bad. The poison takes a day to go into effect, so we won't know the results of drinking it right away. As the king, we have many people who are willing to taste the wine for poison.

Our task is to figure out the least amount of people we would need to taste the wine and figure out exactly which glass of wine has the poison in it. We can assume that the tasters are allowed to drink from as many glasses as we choose. Assume that the glasses are large enough so arbitrarily many tasters can drink from any given glass.

Remember, the task isn't to minimize the amount of tasters who get sick (if it were we would hire 1,000 and have them each taste 1). Rather, it is to minimize the number of tasters we hire.

Hint: It is not necessary to come up with the exact strategy for tasting the glasses. I am only looking for the number of people we would need to figure out which glass the poison is in.


10 tasters.
LongLiveYorke
QUOTE (AcesUp46 @ Friday, November 24th, 2006, 5:22 PM) *
10 tasters.


Would you like to explain your answer?
Shimmering Wang
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 5:10 PM) *
YOU ARE CORRECT, SIR. See, by answering this correctly, you can now get any job you want at Microsoft, any consulting firm, and you an ace your LSAT's (really, all those things are basically riddles like this).

Okay, super hard one here:

(I'm not sure I fully understand the answer, but I'm coming to grips with it)
We are a king holding a party. At this party, we have 1,000 glasses of wine. However, an assassin trying to kill us or ruin our party has put poison in one glass of wine. The poison will leave whoever drinks it very sick, which is bad. The poison takes a day to go into effect, so we won't know the results of drinking it right away. As the king, we have many people who are willing to taste the wine for poison.

Our task is to figure out the least amount of people we would need to taste the wine and figure out exactly which glass of wine has the poison in it. We can assume that the tasters are allowed to drink from as many glasses as we choose. Assume that the glasses are large enough so arbitrarily many tasters can drink from any given glass.

Remember, the task isn't to minimize the amount of tasters who get sick (if it were we would hire 1,000 and have them each taste 1). Rather, it is to minimize the number of tasters we hire.

Hint: It is not necessary to come up with the exact strategy for tasting the glasses. I am only looking for the number of people we would need to figure out which glass the poison is in.


It appears to me that the answer is 1, but it, uh, may take a while. Like, 1000 days.

Wang
DrawingDeadInDM
QUOTE (Shimmering Wang @ Friday, November 24th, 2006, 2:29 PM) *
It appears to me that the answer is 1, but it, uh, may take a while. Like, 1000 days.

Wang


That was my thought.
LongLiveYorke
QUOTE (Shimmering Wang @ Friday, November 24th, 2006, 5:29 PM) *
It appears to me that the answer is 1, but it, uh, may take a while. Like, 1000 days.

Wang


Sorry, I forgot to add that the party is "tomorrow" so we only have one day to do this. In other words, we have to do it all at once. We have to get our tasters to taste the wine, let them go to sleep, and the next day we have to know which one the poison is in based on who got sick and who didn't.

But points for pointing out my riddle's holes.
Shimmering Wang
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 5:34 PM) *
Sorry, I forgot to add that the party is "tomorrow" so we only have one day to do this. In other words, we have to do it all at once. We have to get our tasters to taste the wine, let them go to sleep, and the next day we have to know which one the poison is in based on who got sick and who didn't.

But points for pointing out my riddle's holes.


I assumed there'd be an addended caveat like this.

I call foul, and declare myself winner. I'm doing this because this is the first riddle I haven't immediately known the answer to, and it's making me angry. I'm assuming 999 is not the answer, so I'll keep working.

Wang

EDIT: I'm pretty sure the solution involves MIXING wines, boys, but I'm really REALLY drunk, so it might take me a while to get the answer.
gkunit20
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 4:10 PM) *
YOU ARE CORRECT, SIR. See, by answering this correctly, you can now get any job you want at Microsoft, any consulting firm, and you an ace your LSAT's (really, all those things are basically riddles like this).

Okay, super hard one here:

(I'm not sure I fully understand the answer, but I'm coming to grips with it)
We are a king holding a party. At this party, we have 1,000 glasses of wine. However, an assassin trying to kill us or ruin our party has put poison in one glass of wine. The poison will leave whoever drinks it very sick, which is bad. The poison takes a day to go into effect, so we won't know the results of drinking it right away. As the king, we have many people who are willing to taste the wine for poison.

Our task is to figure out the least amount of people we would need to taste the wine and figure out exactly which glass of wine has the poison in it. We can assume that the tasters are allowed to drink from as many glasses as we choose. Assume that the glasses are large enough so arbitrarily many tasters can drink from any given glass.

Remember, the task isn't to minimize the amount of tasters who get sick (if it were we would hire 1,000 and have them each taste 1). Rather, it is to minimize the number of tasters we hire.

Hint: It is not necessary to come up with the exact strategy for tasting the glasses. I am only looking for the number of people we would need to figure out which glass the poison is in.


Using a random number generator, assign each glass a number, 000 being the glass with the poison and 001-999 being the glasses without the poisen. Run multiple trials (like 100) using the random number generator, and see, on average, how many glasses would have to be drunk to find out. 1 glass = 1 taster.

If you're trying to find out exactly WHICH glass is poisened, can't help you there.


EDIT: running random number trials does not take more than an hour for 100 trials.
AcesUp46
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 2:28 PM) *
Would you like to explain your answer?


I worked backwards. Let n be the number of glasses of wine.

Trivial. When n=2, you just need 1 taster.

When n=3, you need just 2 tasters.

When n=4, you still just need 2 tasters. You can leave out 1 glass (say Glass 4) cos if that Glass is poisonous, then if no one dies, that glass is the one. So 3 glasses left. So you let Taster A taste Glass 1 and Glass 2. While Taster B tasters Glass 3 and Glass 2. If ONLY Taster A dies, then Glass 1 is the culprit. If ONLY Taster B dies, then Glass 3 is the culprit. If BOTH die, then Glass2 is culprit. If NONE die, then Glass 4 it is.

Note that 2 = 2^1.
2^1 < 3 < 2^2 ...Hence 2 tasters is sufficient for n=3 & 4

At this point, I figure that there are plateus at which x number of tasters are sufficient, beyond which, you move to the next level of tasters. ie 2 tasters may be sufficient for n<= 4. And then say 5 tasters is sufficient for n<= 10 for example.

Anyway, I realized that effectively, you're working with powers of 2. And note that 2^9 < 1000 < 2^10

Thus, 10 tasters, since you're need to operate at the 10th power of 2.

EDIT: Don't look at this problem in a linear way. Instead formulate a matrix where each individual taster tastes his unique selection of wine. No 2 tasters are tasting the same portfolio of wine. Hence, by looking at which tasters died, you can pinpoint which bottle of wine is poisonous since your matrix is set up in such a way that all the dead tasters share ONLY 1 glass of wine. Hope my answer is clear enough....
qyayqi
To detect and correct single bit errors requires 10 extra bits per 1000 bit frame.

so acesup should be correct.
Shimmering Wang
Sounds rightish. I came up with 10, but my way was more convoluted.
LongLiveYorke
QUOTE (qyayqi @ Friday, November 24th, 2006, 5:42 PM) *
To detect and correct single bit errors requires 10 extra bits per 1000 bit frame.

so acesup should be correct.



This is the best way to think about it. Our information consists of a series of yes/no's. Either they got sick or they didn't. It's binary. So, we have all binary information. We need to use a certain number if bits to pinpoint exactly which glass it is (each bit is a taster). We can map the problem to pinpointing an exact number. In other words, the question is how many bits do we need to specify the number 1,000. The answer is 10 (2^10 = 1024). Like AcesUp suggested, if I had asked the same problem with 1011, 1015, or 1020, etc glasses, 10 would still be the answer.

Super props to Aces up for answering what I consider to be a very hard problem.
gkunit20
Math riddles blow. Riddles where all the info is given are better. Like this one:


A detective knocks on a man's door. "Is your name John?" the detective asks. "Yes it is," responds the man. "Your brother was murdered yesterday," says the detective. John looks shocked. "Sam's dead?" he said. "But, I just spoke to him last sunday." The detective says, "May I come in?" "Sure," says John. "Please, tell me about the last time you spoke with Sam," the detective asked. "ok," says John. "Last sunday was our family reunion. Everybody I knew from our family was there. I was talking to my brother Phil when Sam walked up and asked me how I was. He seemed perfectly healthy and happy. I don't know why anyone would have wanted to hurt him." "Thank you for your time. Keep in touch," Says the detective. He than leaves. Once he is outside, he calls up his captain. "Captain," he says. "Get me a warrent for John's arrest for the murder of his brother Sam."


Why?
AcesUp46
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 3:02 PM) *
This is the best way to think about it. Our information consists of a series of yes/no's. Either they got sick or they didn't. It's binary. So, we have all binary information. We need to use a certain number if bits to pinpoint exactly which glass it is (each bit is a taster). We can map the problem to pinpointing an exact number. In other words, the question is how many bits do we need to specify the number 1,000. The answer is 10 (2^10 = 1024). Like AcesUp suggested, if I had asked the same problem with 1011, 1015, or 1020, etc glasses, 10 would still be the answer.

Super props to Aces up for answering what I consider to be a very hard problem.


Do I get a super cookie???
qyayqi
QUOTE (gkunit20 @ Friday, November 24th, 2006, 3:13 PM) *
Math riddles blow. Riddles where all the info is given are better. Like this one:
A detective knocks on a man's door. "Is your name John?" the detective asks. "Yes it is," responds the man. "Your brother was murdered yesterday," says the detective. John looks shocked. "Sam's dead?" he said. "But, I just spoke to him last sunday." The detective says, "May I come in?" "Sure," says John. "Please, tell me about the last time you spoke with Sam," the detective asked. "ok," says John. "Last sunday was our family reunion. Everybody I knew from our family was there. I was talking to my brother Phil when Sam walked up and asked me how I was. He seemed perfectly healthy and happy. I don't know why anyone would have wanted to hurt him." "Thank you for your time. Keep in touch," Says the detective. He than leaves. Once he is outside, he calls up his captain. "Captain," he says. "Get me a warrent for John's arrest for the murder of his brother Sam."
Why?


more than one brother & he knew which was dead.
RodReynolds
QUOTE (gkunit20 @ Friday, November 24th, 2006, 8:13 PM) *
Math riddles blow. Riddles where all the info is given are better. Like this one:
A detective knocks on a man's door. "Is your name John?" the detective asks. "Yes it is," responds the man. "Your brother was murdered yesterday," says the detective. John looks shocked. "Sam's dead?" he said. "But, I just spoke to him last sunday." The detective says, "May I come in?" "Sure," says John. "Please, tell me about the last time you spoke with Sam," the detective asked. "ok," says John. "Last sunday was our family reunion. Everybody I knew from our family was there. I was talking to my brother Phil when Sam walked up and asked me how I was. He seemed perfectly healthy and happy. I don't know why anyone would have wanted to hurt him." "Thank you for your time. Keep in touch," Says the detective. He than leaves. Once he is outside, he calls up his captain. "Captain," he says. "Get me a warrent for John's arrest for the murder of his brother Sam."
Why?


Took me a few reads, but I think I got it, I'll write it in white.

dammit, nm



Detective only mentions a brother, doesn't say it was Sam. John somehow knows it was Sam, even though he has more than one brother.
LongLiveYorke
QUOTE (AcesUp46 @ Friday, November 24th, 2006, 6:14 PM) *
Do I get a super cookie???


Please wait 6-8 weeks for delivery.
AcesUp46
This is an easy one.

There are 3 girls that you wanna have sex with. But you only have 2 condoms. How do you have sex with all 3 of them (separately) without getting STDs from them or passing STDs between them or giving them STDs??
LongLiveYorke
QUOTE (gkunit20 @ Friday, November 24th, 2006, 6:13 PM) *
Math riddles blow.



Okay, last one then. If you get the answer, PM it to me. I want others to get a chance at it first. Here it is?

The real part of any non-trivial zero of the Riemann zeta function is ½. Why?

Recall the zeta function is defined by



and non trivial zeros are those zeros not occurring at the negative even integers in the complex plane

This one shouldn't be that hard if you really think about it.
Shimmering Wang
QUOTE (AcesUp46 @ Friday, November 24th, 2006, 6:27 PM) *
This is an easy one.

There are 3 girls that you wanna have sex with. But you only have 2 condoms. How do you have sex with all 3 of them (separately) without getting STDs from them or passing STDs between them or giving them STDs??


All these riddles have stupidly easy solutions, because nobody is giving us all the information.
gkunit20
QUOTE (RodReynolds @ Friday, November 24th, 2006, 5:19 PM) *
Took me a few reads, but I think I got it, I'll write it in white.

dammit, nm
Detective only mentions a brother, doesn't say it was Sam. John somehow knows it was Sam, even though he has more than one brother.



Congrats! You win a cookie.


QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 5:28 PM) *
Okay, last one then. If you get the answer, PM it to me. I want others to get a chance at it first. Here it is?

The real part of any non-trivial zero of the Riemann zeta function is ½. Why?

This one shouldn't be that hard if you really think about it.


WTF? Can you repeat that in English please?
Shimmering Wang
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 6:28 PM) *
Okay, last one then. If you get the answer, PM it to me. I want others to get a chance at it first. Here it is?

The real part of any non-trivial zero of the Riemann zeta function is ½. Why?

Recall the zeta function is defined by



and non trivial zeros are those zeros not occurring at the negative even integers in the complex plane

This one shouldn't be that hard if you really think about it.


Dude, it's tautological.

(When in doubt, this response works for anything that should be apparent to a non-moron, but isn't [because I am a moron])
AcesUp46
QUOTE (LongLiveYorke @ Friday, November 24th, 2006, 3:28 PM) *
Okay, last one then. If you get the answer, PM it to me. I want others to get a chance at it first. Here it is?

The real part of any non-trivial zero of the Riemann zeta function is ½. Why?

Recall the zeta function is defined by



and non trivial zeros are those zeros not occurring at the negative even integers in the complex plane

This one shouldn't be that hard if you really think about it.


lol....I remembered this from math class a while back. Basically, if you get the answer, you'll definitely win the Fields Medal and quite a fair sum of money.
gkunit20
It seems we have different tastes in riddles. I like riddles where you know the answer, but you need to think about it before you can get it.


There is a barrel, weighing 20 pounds. Susie came and put somethimg in the barrel, making the barrel lighter than 20 pounds. what did Susie put in the barrel?
AcesUp46
QUOTE (gkunit20 @ Friday, November 24th, 2006, 3:37 PM) *
It seems we have different tastes in riddles. I like riddles where you know the answer, but you need to think about it before you can get it.
There is a barrel, weighing 20 pounds. Susie came and put somethimg in the barrel, making the barrel lighter than 20 pounds. what did Susie put in the barrel?


Was there some fuel in the barrel and Susie put a fire in the barrel?
timwakefield
QUOTE (gkunit20 @ Friday, November 24th, 2006, 3:37 PM) *
There is a barrel, weighing 20 pounds. Susie came and put somethimg in the barrel, making the barrel lighter than 20 pounds. what did Susie put in the barrel?


A balloon filled with helium. Even if it's not the answer you're looking for, it's totally correct.
DrawingDeadInDM
QUOTE (gkunit20 @ Friday, November 24th, 2006, 3:37 PM) *
It seems we have different tastes in riddles. I like riddles where you know the answer, but you need to think about it before you can get it.
There is a barrel, weighing 20 pounds. Susie came and put somethimg in the barrel, making the barrel lighter than 20 pounds. what did Susie put in the barrel?


Her hand.

..displacing the water that was in the barrel.

Oh.
gkunit20
QUOTE (AcesUp46 @ Friday, November 24th, 2006, 5:38 PM) *
Was there some fuel in the barrel and Susie put a fire in the barrel?



QUOTE (timwakefield @ Friday, November 24th, 2006, 5:39 PM) *
A balloon filled with helium. Even if it's not the answer you're looking for, it's totally correct.


Both of you are incorrect.

BTW, a balloon filled with helium would make the barrel lighter, but not by 20 pounds.
AcesUp46
QUOTE (gkunit20 @ Friday, November 24th, 2006, 3:41 PM) *
Both of you are incorrect.

BTW, a balloon filled with helium would make the barrel lighter, but not by 20 pounds.


lol. HOLE.
What's wrong with my fire answer btw??
gkunit20
QUOTE (AcesUp46 @ Friday, November 24th, 2006, 5:42 PM) *
lol. HOLE.


Bravo. There was water in the barrel, so fire wouldn't work.


This one shouldn't be too hard.

What is so fragile that when you say its name you break it?
DrawingDeadInDM
QUOTE (DrawingDeadInDM @ Friday, November 24th, 2006, 3:41 PM) *
Her hand.

..displacing the water that was in the barrel.

Oh.


This is right, too, if hole is correct.


QUOTE (gkunit20 @ Friday, November 24th, 2006, 3:43 PM) *
Bravo.
This one shouldn't be too hard.

What is so fragile that when you say its name you break it?


Silence, obv.
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