Your still borderline though.

you done good
-1 retard points

but sincve the DN riddle was already posted I can't take your word for comming up with the answer.
NO RETARD POINTS FOR YOU!

Graham's number is like my favorite mathematical thing ever. I've slipped in a few Graham's number references on the Forums when no one's looking.

"What are the chances of him hitting that two outer on the river?!?!?"

"About one in Graham's number."

The best part about Graham's number is the fact that it is an upper bound. That would be like me telling my girlfriend that she doesn't look fat in that dress because she's smaller than a blue whale.

QFMFT

If it was like, you know, a lower bound, then it would just be, um, you know, lame.

That's nothing. What'll really bake your noodle is this:

So, we agree that there are infinite natural numbers (1,2,3... etc). Obviously, right? And we agree that there are infinitely many real numbers (as in every possible decimal expansion with negatives and zero included).

But what if we are only talking about integers (... -3, -2, -1, 0, 1, 2, 3...). Are there more integers than natural numbers (1, 2, 3...). You will probably at first guess say yes, because integers include negatives. So, there are twice as many. But mathematically, you'd be wrong. There are the same number. How do we know? Well, the definition of the type of infinity that we're talking about is being able to count the infinite amount of things that we're talking about. In other words, if you can use natural numbers (1, 2, 3... etc) to count something, even if there is infinitely many of that thing, then there is the same amount of that thing than there are natural numbers (infinitely many, but the same type of infinity). I would propose that it would be easy to count all the integers by assigning them natural numbers (this is called mapping, or more specifically one to one correspondence mapping, or using a bijection). As an example, I would just label 0 with a 1, 1 with a 2, -1 with a 3, 2 with a 4, -2 with a 5, 3 with a 6, -3 with a 7, etc. If you do this, there is no doubt as to which number each integer would get (it would take you a while to actually figure it out maybe but the answer would be definite). So, there are therefore the same number of integers as there are natural numbers. Cool, isn't it.


(if you really want to shoot yourself in the face, consider the rational numbers, or every number that can be described by a fraction of integers)

nah that stuff isn't that cool, infinity blows. Pi is the shiznit, it's everywhere, close second would be e, but Pi makes the world go round, I love Pi, I'm in it for Pi!

and following the riddle theme but not at all really

I answered that one Waaaaaaaaaaaaaaaaay before you.

Simple. Ask one if troyo is gay, if he says yes, he is teh saint. If he says no, then he is the devil.

Strangest thing happened last night.
Went home and did a crossword (two speed - normal & cryptic clues)
and this was one of them. Very strange.

FSDLIJITNWE:FINMWI:LIUTWIWEPURWP!!!!!!!!!!!!!!!!!!!!!!!!!!!

Your Retarded. Go check page eleven. Unless I'm missing something.

ZOMGWTFROFLMAOQFTPOTDAINECGGVNHIGHN!!11!1!

I can't decipher your acronym though. Is it a riddle?

Think you will appreciate this...



(and yes, I realize I didnt fubar my name... I dont care.)

for the one i posted a while ago, 5 minutes is correct

If it takes one man 3 hours to dig a hole. How long would it take 3 men to dig half of a hole

1/2 hour.
If by "half a hole" you mean one half as deep as the one it takes one man 3 hours to dig

no, by 'half of a hole' I meant 'half of a hole'

It's not code, my fingers are just to fat to hit the keys I want to, and I ended up hitting a lot of keys.



Shouldn't it only take a second or 2? I mean even if they hole is only 1 inch wide or deep, it's still a hole.

There is no such thing as half a hole!

Man, I'm so clever, if clever means "knowing many famous riddles that are actually trick questions."

This is one from page 1 that nobody has answer correctly yet, and yes, there IS an answer

a woman has two children, and a homocidal maniac tells her she can only keep one, which one does she let him kill?

the ugly one

hooray some one finally got it



The sound of humour, happiness, joy, thrilled

Now add an ‘s’ it’s carnage, massacred, killed.

GreatDane?

Really though, I vaguely remember that the homocidal maciac is one of her sons, and she tells him to die?

I've had enough coronas tonight to make beans jealous, so I'm probably retarded.


Awesome!

GreatDane is also acceptable

the riddle is from the Family Guy episode 'E Peterbus Unum' in which Peter finds out he is not part of U.S. and thus, makes his own country called 'Petoria'

The scene is at the very beginning of the episode

Peter: Okay, here's a riddle, a woman has two children, and a homicidal maniac tells her she can only keep one. Which one does she let him kill?

Brain: Peter, that's not a riddle...that's just terrible

Peter: Wrong! The ugly one.

This is me being a huge fan of Family Guy, feeling like a mrono for not knowing the answer.

But I already explained why I didn't catch it. There is so much e-hate going on tonight, I am so entertained. I was thinking of playing some micro FullTilt, but I'd be too busy laughing at GreatDane to play well. Not that I do anyway, but meh.

BAC: 8 coronas, .5 of a fifth of crown. Too bad I will hate myself when I have to wake up in five hours. It's worth it though!

bump

ha ha ha

Considering we're on page 7...

Laughter + S = Slaughter

Some people have different sized pages, so for some people threads are "longer" than others.

EVERYONE. LISTEN UP to my favorite riddle ever. This is complicated but really tight.

There are 3 couples on an island. The rule of the island is that if the man catches his wife cheating, he will have her hanged at noon that day. It turns out that all three wives are cheating, but each husband can only see the other wives cheating and cannot observe his own. So, husband A sees B and C cheating, B sees A and C cheating, C sees A and B cheating, but never their own.

But, on January 1st, God comes down to the island. "Husbands," says he, "At least one wife on this island is cheating."

Do the wives die? If so, who? If so, when? And why?

An interesting hint here is to think about what extra information the men actually gained from God's words.

So, since everybody sees someone else cheating, God's words aren't very troubling at first. A, for instance, says to himself that both B and C are cheating, so God's words don't necesarily mean that A (his wife) is cheating. The same goes for B and C.

So, on January 1st no one dies.

January 2nd:

Now it gets interesting. Because no one was killed, it means that at least two wives are cheating. For example, if only one wife was cheating, then the husband of that wife would see that no one was cheating on January 1st, and therefore with the knowledge that someone was cheating, would know that his wife was cheating. This applies to all three.

But, this isn't so bad. After all, each of them sees two people cheating, so it could only be those two who are cheating. For instance, A sees B and C cheating, so he figures that if at least 2 are cheating, it could be that only B and C are cheating, so he's okay.

So, on January 2nd, no one dies.

January 3rd:

The fun part. Since no one died before, it must be the case that everybody sees two people cheating. After all, if there were EXACTLY two people cheating, then one of them would only see on person cheating and therefore know that his wife was cheating and would therefore kill his wife. However, no one died on January 2nd, so therefore they all see two people cheating.

All three wives are hung on January 3rd at Noon.

The husbands all realize that they are sleeping with each other's wives and kill each other. The women then go lesbian for the remainder of their lives on the island.

Here's an amazingly difficult and terrible riddle

It wasted a lot of my time since I couldn't stop working on it until I figured it out. Here's how it goes:

- In a street there are five houses, painted five different colors.

- In each house lives a person of different nationality

- These five homeowners each drink a different kind of beverage, smoke different brand of cigar and keep a different pet.


Necessary clues:

1. The British man lives in a red house.
2. The Swedish man keeps dogs as pets.
3. The Danish man drinks tea.
4. The Green house is next to, and on the left of the White house.
5. The owner of the Green house drinks coffee.
6. The person who smokes Pall Mall rears birds.
7. The owner of the Yellow house smokes Dunhill.
8. The man living in the center house drinks milk.
9. The Norwegian lives in the first house.
10. The man who smokes Blends lives next to the one who keeps cats.
11. The man who keeps horses lives next to the man who smokes Dunhill.
12. The man who smokes Blue Master drinks beer.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The Blends smoker lives next to the one who drinks water.

The question is this: Who owns the fish?

The Norwegian

Does the American live in the White House?

There is no American.

It's the German.

have you heard this riddle before? if not, you are truly a sick nasty human being.

No, but my brain was very warmed because I read this one just after solving the one that I posted above.

House-Color-Nation-Beverage-Cigar-Pet

1st-Yellow-Norwegian-Water-Dunhill-Cats

2nd-Blue-Danish-Tea-Blends-Horses

3rd-Red-British-Milk-Pall Mall-Birds

4th-Green-German-Coffee-Prince-Fish

5th-White-Swedish-Beer-Blue Master-Dogs

German should be correct

or its a trick question and none of them own one

Pretty sure that this is correct. Yes, it's the German. Well, I thought it was a bit hard.

This riddle was first made by Einstein. He claimed that only 2% of people would be able to solve it.

People usually find it somewhat fun but very annoying, or just very annoying.

It takes a little trial and error, but I got there in the end. Had to make a guess on that damn Brit in the red house.

this riddle was posted in another thread a while back. I'm not saying people got the answer from there. I'm just saying it might not be the first time these people saw this riddle.

3+6+8+7 = 4

explain

could be golf scores on four par 5's.

3 = -2, 6 = +1, 8 = +3, 7 = +2. -2 + 1 + 3 + 2 = 4 over par.

good thinking, but no

3+6+8+7= 22 --> 2+2 = 4

3+6+8+7 = 24

duh

weeeeeeeeeeeeeee, this is why we dont post after long sessions of homework. ooooops



got it this time though...


there are 4 numbers: 3,6,8, and 7.

Congruent modulo 20?