_Great_Dane_
Friday, November 10th, 2006, 3:27 PM
QUOTE (bigkeenanh @ Friday, November 10th, 2006, 4:58 PM)

Assuming I can't win if I'm called...
betting $40 into a $30 pot, how often do I have to win in order for this play to be profitable.
Please provide how you did this.
Thanks

QUOTE (bigkeenanh @ Friday, November 10th, 2006, 5:29 PM)

I asked because a play I've been trying a few times ends up betting 40 to win 30 (arbitrary numbers, but same %s).
Heads up pot, hero has position. Villain took lead preflop.
Flop pot = 10
Villain bets $5, hero calls
turn pot = 20
Villain bets $10, hero raises to $40
I'm looking at this again because the op gave some more info in his second post:
Here are the "givens" that I'm working with: you're heads up, and $10 of the $30 pot was from you, and you're all in for $40, assuming that you can't win if you're called, you'll be betting $50 ($10 + $40) to win $20 ($5 + $5 + $10) of someone else's money. In order to be "profitable" I feel as though we need to include all money invested during the hand.
$50 of your money divided by $20 of someone else's money = 2 1/2. You'll need to win, in this scenario, 2 1/2 times for every 1 time that you lose (or win 5 times for every 2 losses) to break even. Winning 5 times out of 7 = about 71% of the time.
This is just a simple way to look at it based on my understanding of the given circumstances. Of course, it's always important to check our math: winning 5 times, at $20 profit per hand, = $100 profit. Losing 2 times, at $50 lost per hand, = $100 lost.