question about the math..... if someone needs runner runner Q10 to make a straight does the math go 4/47 x 4/46 = ? any help would be appreciated... should be easy but im slow this morning

No, it's a bit better than that. 4/47 * 4/46 assumes that it must be QT in that order.

There are 8 turn cards that help him, for each of those 8 turn cards, there are then 4 river cards that help.

so 8/47 x 4/46 = .0148 or 1.5% chance into odds that would be 8*4/47*46 or 32/2162 = 67.5:1?

I calculate relevant statistics all the time. Runner Runner is not one of them. This is simply because it's never a good bet and never something you should be fearful about when playing. Everytime someone runner-runners you, thank your stars they are at your table.

Think of it this way, if there was a casino game with a 60% chance to double your money, would you play it? How about 80% chance? 95% chance? Of course you'd play in any and all of the above situations. That's what people who runner-runner you are doing. They are gambling for half the pot (or maybe a tad more) at a huge disadvantage. People who gamble this way go broke, period.

I will try an answer, please correct my math if I am wrong:

Let's assume that it is an all-in situation versus two players and you know that both players do not have Q-T in their pocket (because they turn their card on the all-in).
So 4 Q remaining and 4 T remaining with 45 possibilities (52 cards - 3 flop - 2 pockets - 2 pockets)

1 - (37/45 * 40/44) = 25.25% = 74.75:25.25 = 2.96:1

Am I right?

You can only remove your cards from the equation. YOu don't know what your oopponent has. Or if you are saying they are turned face up already, then yes, I believe you calculated correctly.