antistuff
Monday, June 9th, 2008, 3:21 PM
QUOTE (dingas @ Monday, June 9th, 2008, 6:44 PM)

You can do some math and determine how often villain has to have the nuts to make folding correct here.
You have to call $20 to win $40.
If he has the nuts you have 23% equity, if he doesn't have it, he may or may not be drawing live to a full house - I will estimate his equity at about 8%.
If he has it, your total expectation is (40)(.23) - (20)(.77) = -6.2
If he does not have it, your expectation is (40)(.92) - (20)(.08) = 35.2
Let x represent the chance that he has the nuts: your expectation becomes EV = (-6.2)x + 35.2(1-x)
Set EV = 0 and solve for x
35.2 = 41.4x
x = 0.8502
Thus, you have a positive expectation if he has the nuts 85% of the time or less. This whole analysis completely ignores implied odds, however, which complicate things considerably. Probably the implied odds somewhat devalue calling here, because you are more likely to be paying off on the river than getting paid off.
I vote for calling here because it is more fun. Objectively, a fold may be the best play, but I don't think that either play is really a big mistake in the long-run.
how does it work out if we toss our whole stack in? i am assuming we have zero fold equity.
85% is an awful lot.